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2\sqrt{3}\sqrt{2}+2\left(\sqrt{3}\right)^{2}
Use the distributive property to multiply 2\sqrt{3} by \sqrt{2}+\sqrt{3}.
2\sqrt{6}+2\left(\sqrt{3}\right)^{2}
To multiply \sqrt{3} and \sqrt{2}, multiply the numbers under the square root.
2\sqrt{6}+2\times 3
The square of \sqrt{3} is 3.
2\sqrt{6}+6
Multiply 2 and 3 to get 6.