Solve for x
x=-\frac{\sqrt{6}}{3}\approx -0.816496581
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2\sqrt{3}x+2\sqrt{2}=0
Factor 8=2^{2}\times 2. Rewrite the square root of the product \sqrt{2^{2}\times 2} as the product of square roots \sqrt{2^{2}}\sqrt{2}. Take the square root of 2^{2}.
2\sqrt{3}x=-2\sqrt{2}
Subtract 2\sqrt{2} from both sides. Anything subtracted from zero gives its negation.
\frac{2\sqrt{3}x}{2\sqrt{3}}=-\frac{2\sqrt{2}}{2\sqrt{3}}
Divide both sides by 2\sqrt{3}.
x=-\frac{2\sqrt{2}}{2\sqrt{3}}
Dividing by 2\sqrt{3} undoes the multiplication by 2\sqrt{3}.
x=-\frac{\sqrt{6}}{3}
Divide -2\sqrt{2} by 2\sqrt{3}.
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