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2\sqrt{3}-\frac{\sqrt{3}}{2\left(\sqrt{3}\right)^{2}}
Rationalize the denominator of \frac{1}{2\sqrt{3}} by multiplying numerator and denominator by \sqrt{3}.
2\sqrt{3}-\frac{\sqrt{3}}{2\times 3}
The square of \sqrt{3} is 3.
2\sqrt{3}-\frac{\sqrt{3}}{6}
Multiply 2 and 3 to get 6.
\frac{11}{6}\sqrt{3}
Combine 2\sqrt{3} and -\frac{\sqrt{3}}{6} to get \frac{11}{6}\sqrt{3}.