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\sqrt{3}\left(\sqrt{12}+\sqrt{3}\right)
Cancel out 2 and 2.
\sqrt{3}\sqrt{12}+\left(\sqrt{3}\right)^{2}
Use the distributive property to multiply \sqrt{3} by \sqrt{12}+\sqrt{3}.
\sqrt{3}\sqrt{3}\sqrt{4}+\left(\sqrt{3}\right)^{2}
Factor 12=3\times 4. Rewrite the square root of the product \sqrt{3\times 4} as the product of square roots \sqrt{3}\sqrt{4}.
3\sqrt{4}+\left(\sqrt{3}\right)^{2}
Multiply \sqrt{3} and \sqrt{3} to get 3.
3\times 2+\left(\sqrt{3}\right)^{2}
Calculate the square root of 4 and get 2.
6+\left(\sqrt{3}\right)^{2}
Multiply 3 and 2 to get 6.
6+3
The square of \sqrt{3} is 3.
9
Add 6 and 3 to get 9.