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2\times 3\sqrt{3}+\sqrt[3]{\left(-5\right)^{3}}
Factor 27=3^{2}\times 3. Rewrite the square root of the product \sqrt{3^{2}\times 3} as the product of square roots \sqrt{3^{2}}\sqrt{3}. Take the square root of 3^{2}.
6\sqrt{3}+\sqrt[3]{\left(-5\right)^{3}}
Multiply 2 and 3 to get 6.
6\sqrt{3}+\sqrt[3]{-125}
Calculate -5 to the power of 3 and get -125.
6\sqrt{3}-5
Calculate \sqrt[3]{-125} and get -5.