Solve 2sqrt{2}+frac{sqrt{6}}{3}

$$2 \sqrt { 2 } + \frac { \sqrt { 6 } } { 3 }$$

Evaluate

$$\frac{\sqrt{6}\left(2\sqrt{3}+1\right)}{3}\approx 3.644923706$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Multiply 2\sqrt{2} times \frac{3}{3}.

$$\frac{3\times 2\sqrt{2}}{3}+\frac{\sqrt{6}}{3}$$

Since \frac{3\times 2\sqrt{2}}{3} and \frac{\sqrt{6}}{3} have the same denominator, add them by adding their numerators.

$$\frac{3\times 2\sqrt{2}+\sqrt{6}}{3}$$

Do the multiplications in 3\times 2\sqrt{2}+\sqrt{6}.

$$\frac{6\sqrt{2}+\sqrt{6}}{3}$$

Factor

$$\frac{\sqrt{6} {(\sqrt{2} \sqrt{6} + 1)}}{3} = 3.6449237056739157$$