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2\times 2\sqrt{3}-9\sqrt{\frac{1}{27}}+3\sqrt{18}
Factor 12=2^{2}\times 3. Rewrite the square root of the product \sqrt{2^{2}\times 3} as the product of square roots \sqrt{2^{2}}\sqrt{3}. Take the square root of 2^{2}.
4\sqrt{3}-9\sqrt{\frac{1}{27}}+3\sqrt{18}
Multiply 2 and 2 to get 4.
4\sqrt{3}-9\times \frac{\sqrt{1}}{\sqrt{27}}+3\sqrt{18}
Rewrite the square root of the division \sqrt{\frac{1}{27}} as the division of square roots \frac{\sqrt{1}}{\sqrt{27}}.
4\sqrt{3}-9\times \frac{1}{\sqrt{27}}+3\sqrt{18}
Calculate the square root of 1 and get 1.
4\sqrt{3}-9\times \frac{1}{3\sqrt{3}}+3\sqrt{18}
Factor 27=3^{2}\times 3. Rewrite the square root of the product \sqrt{3^{2}\times 3} as the product of square roots \sqrt{3^{2}}\sqrt{3}. Take the square root of 3^{2}.
4\sqrt{3}-9\times \frac{\sqrt{3}}{3\left(\sqrt{3}\right)^{2}}+3\sqrt{18}
Rationalize the denominator of \frac{1}{3\sqrt{3}} by multiplying numerator and denominator by \sqrt{3}.
4\sqrt{3}-9\times \frac{\sqrt{3}}{3\times 3}+3\sqrt{18}
The square of \sqrt{3} is 3.
4\sqrt{3}-9\times \frac{\sqrt{3}}{9}+3\sqrt{18}
Multiply 3 and 3 to get 9.
4\sqrt{3}-\sqrt{3}+3\sqrt{18}
Cancel out 9 and 9.
3\sqrt{3}+3\sqrt{18}
Combine 4\sqrt{3} and -\sqrt{3} to get 3\sqrt{3}.
3\sqrt{3}+3\times 3\sqrt{2}
Factor 18=3^{2}\times 2. Rewrite the square root of the product \sqrt{3^{2}\times 2} as the product of square roots \sqrt{3^{2}}\sqrt{2}. Take the square root of 3^{2}.
3\sqrt{3}+9\sqrt{2}
Multiply 3 and 3 to get 9.