Solve 2sin60^circ+3cot60^circ*sin90^circ

$$2 \sin 60 ^ { \circ } + 3 \cot 60 ^ { \circ } \times \sin 90 ^ { \circ }$$

Evaluate

$$2\sqrt{3}\approx 3.464101615$$

Solution Steps

Get the value of \sin(60) from trigonometric values table.

$$2\times \frac{\sqrt{3}}{2}+3\cot(60\sin(90))$$

Cancel out 2 and 2.

$$\sqrt{3}+3\cot(60\sin(90))$$

Get the value of \sin(90) from trigonometric values table.

$$\sqrt{3}+3\cot(60\times 1)$$

Multiply 60 and 1 to get 60.

$$\sqrt{3}+3\cot(60)$$

Get the value of \cot(60) from trigonometric values table.

$$\sqrt{3}+3\times \frac{\sqrt{3}}{3}$$

Cancel out 3 and 3.

$$\sqrt{3}+\sqrt{3}$$

Combine \sqrt{3} and \sqrt{3} to get 2\sqrt{3}.

$$2\sqrt{3}$$