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Solve for x (complex solution)
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Solve for x
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Solve for α (complex solution)
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Solve for α
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2\sin(\frac{1}{2})x=\alpha
The equation is in standard form.
\frac{2\sin(\frac{1}{2})x}{2\sin(\frac{1}{2})}=\frac{\alpha }{2\sin(\frac{1}{2})}
Divide both sides by 2\sin(\frac{1}{2}).
x=\frac{\alpha }{2\sin(\frac{1}{2})}
Dividing by 2\sin(\frac{1}{2}) undoes the multiplication by 2\sin(\frac{1}{2}).
2\sin(\frac{1}{2})x=\alpha
The equation is in standard form.
\frac{2\sin(\frac{1}{2})x}{2\sin(\frac{1}{2})}=\frac{\alpha }{2\sin(\frac{1}{2})}
Divide both sides by 2\sin(\frac{1}{2}).
x=\frac{\alpha }{2\sin(\frac{1}{2})}
Dividing by 2\sin(\frac{1}{2}) undoes the multiplication by 2\sin(\frac{1}{2}).
\alpha =2\sin(\frac{1}{2})x
Swap sides so that all variable terms are on the left hand side.
\alpha =2\sin(\frac{1}{2})x
Swap sides so that all variable terms are on the left hand side.