Solve for y
y=\frac{400-\pi x^{2}}{\pi x}
x\neq 0
Solve for x
x=\frac{\sqrt{y^{2}+\frac{1600}{\pi }}-y}{2}
x=\frac{-\sqrt{y^{2}+\frac{1600}{\pi }}-y}{2}
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2\pi xy=800-2\pi x^{2}
Subtract 2\pi x^{2} from both sides.
\frac{2\pi xy}{2\pi x}=\frac{800-2\pi x^{2}}{2\pi x}
Divide both sides by 2\pi x.
y=\frac{800-2\pi x^{2}}{2\pi x}
Dividing by 2\pi x undoes the multiplication by 2\pi x.
y=-x+\frac{400}{\pi x}
Divide 800-2\pi x^{2} by 2\pi x.
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