Evaluate
\frac{36\ln(2)\ln(3)-8\ln(2)\ln(5)+2\ln(5)^{2}+7\ln(10)^{2}-10\ln(2)^{2}}{\ln(10)^{2}}\approx 10.558241185
Factor
\frac{36 \log_{e} {(2)} \log_{e} {(3)} - 8 \log_{e} {(2)} \log_{e} {(5)} + 2 \log_{e} {(5)} ^ {2} + 7 \log_{e} {(10)} ^ {2} - 10 \log_{e} {(2)} ^ {2}}{\log_{e} {(10)} ^ {2}} = 10.558241184652543
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