Evaluate
\frac{2\left(\ln(5)\ln(\frac{20736}{5})-\ln(2)\ln(3)+4\ln(2)^{2}+\ln(10)^{2}\right)}{\ln(10)^{2}}\approx 7.495101276
Factor
\frac{2 {(\log_{e} {(5)} \log_{e} {(\frac{20736}{5})} - \log_{e} {(2)} \log_{e} {(3)} + 4 \log_{e} {(2)} ^ {2} + \log_{e} {(10)} ^ {2})}}{\log_{e} {(10)} ^ {2}} = 7.495101275747824
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