Solve 2leqc(5*10)+(15*12)+(12*10)

$$2 \leq c ( 5 \times 10 ) + ( 15 \times 12 ) + ( 12 \times 10 )$$

Solve for c

$$c\geq -\frac{149}{25}$$

Solution Steps

Multiply 15 and 12 to get 180. Multiply 12 and 10 to get 120.

$$2\leq c\times 5\times 10+180+120$$

Multiply 5 and 10 to get 50.

$$2\leq c\times 50+180+120$$

Add 180 and 120 to get 300.

$$2\leq c\times 50+300$$

Swap sides so that all variable terms are on the left hand side. This changes the sign direction.

$$c\times 50+300\geq 2$$

Subtract 300 from both sides.

$$c\times 50\geq 2-300$$

Subtract 300 from 2 to get -298.

$$c\times 50\geq -298$$

Divide both sides by 50. Since 50 is positive, the inequality direction remains the same.

$$c\geq \frac{-298}{50}$$

Reduce the fraction \frac{-298}{50} to lowest terms by extracting and canceling out 2.

$$c\geq -\frac{149}{25}$$