Solve 2left(left(2+3-5right)^2-((2)(2/1)-(9+5)right)left(2^2-1right)

$$2 \left( { \left( 2+3-5 \right) }^{ 2 } -((2)( \frac{ 2 }{ 1 } )-(9+5) \right) \left( { 2 }^{ 2 } -1 \right)$$

Evaluate

$$60$$

Solution Steps

Add 2 and 3 to get 5.

$$2\left(\left(5-5\right)^{2}-\left(2\times \frac{2}{1}-\left(9+5\right)\right)\left(2^{2}-1\right)\right)$$

Subtract 5 from 5 to get 0.

$$2\left(0^{2}-\left(2\times \frac{2}{1}-\left(9+5\right)\right)\left(2^{2}-1\right)\right)$$

Calculate 0 to the power of 2 and get 0.

$$2\left(0-\left(2\times \frac{2}{1}-\left(9+5\right)\right)\left(2^{2}-1\right)\right)$$

Anything divided by one gives itself.

$$2\left(0-\left(2\times 2-\left(9+5\right)\right)\left(2^{2}-1\right)\right)$$

Multiply 2 and 2 to get 4.

$$2\left(0-\left(4-\left(9+5\right)\right)\left(2^{2}-1\right)\right)$$

Add 9 and 5 to get 14.

$$2\left(0-\left(4-14\right)\left(2^{2}-1\right)\right)$$

Subtract 14 from 4 to get -10.

$$2\left(0-\left(-10\left(2^{2}-1\right)\right)\right)$$

Calculate 2 to the power of 2 and get 4.

$$2\left(0-\left(-10\left(4-1\right)\right)\right)$$

Subtract 1 from 4 to get 3.

$$2\left(0-\left(-10\times 3\right)\right)$$

Multiply -10 and 3 to get -30.

$$2\left(0-\left(-30\right)\right)$$

The opposite of -30 is 30.

$$2\left(0+30\right)$$

Add 0 and 30 to get 30.

$$2\times 30$$

Multiply 2 and 30 to get 60.

$$60$$

Factor

$$2^{2}\times 3\times 5$$