Solve 23/9+912/18

$$2 \frac{ 3 }{ 9 } +9 \frac{ 12 }{ 18 }$$

Evaluate

$$12$$

Solution Steps

Multiply 2 and 9 to get 18.

$$\frac{18+3}{9}+\frac{9\times 18+12}{18}$$

Add 18 and 3 to get 21.

$$\frac{21}{9}+\frac{9\times 18+12}{18}$$

Reduce the fraction \frac{21}{9} to lowest terms by extracting and canceling out 3.

$$\frac{7}{3}+\frac{9\times 18+12}{18}$$

Multiply 9 and 18 to get 162.

$$\frac{7}{3}+\frac{162+12}{18}$$

Add 162 and 12 to get 174.

$$\frac{7}{3}+\frac{174}{18}$$

Reduce the fraction \frac{174}{18} to lowest terms by extracting and canceling out 6.

$$\frac{7}{3}+\frac{29}{3}$$

Since \frac{7}{3} and \frac{29}{3} have the same denominator, add them by adding their numerators.

$$\frac{7+29}{3}$$

Add 7 and 29 to get 36.

$$\frac{36}{3}$$

Divide 36 by 3 to get 12.

$$12$$

Factor

$$2^{2}\times 3$$