Solve 21/3*0*25+2/7div(1.4-5/7)=

$$2 \frac{ 1 }{ 3 } \times 0 \cdot 25+ \frac{ 2 }{ 7 } \div (1.4- \frac{ 5 }{ 7 } )=$$

Evaluate

$$\frac{5}{12}\approx 0.416666667$$

Solution Steps

Multiply 2 and 3 to get 6.

$$\frac{6+1}{3}\times 0\times 25+\frac{\frac{2}{7}}{1.4-\frac{5}{7}}$$

Add 6 and 1 to get 7.

$$\frac{7}{3}\times 0\times 25+\frac{\frac{2}{7}}{1.4-\frac{5}{7}}$$

Multiply \frac{7}{3} and 0 to get 0.

$$0\times 25+\frac{\frac{2}{7}}{1.4-\frac{5}{7}}$$

Multiply 0 and 25 to get 0.

$$0+\frac{\frac{2}{7}}{1.4-\frac{5}{7}}$$

Convert decimal number 1.4 to fraction \frac{14}{10}. Reduce the fraction \frac{14}{10} to lowest terms by extracting and canceling out 2.

$$0+\frac{\frac{2}{7}}{\frac{7}{5}-\frac{5}{7}}$$

Least common multiple of 5 and 7 is 35. Convert \frac{7}{5} and \frac{5}{7} to fractions with denominator 35.

$$0+\frac{\frac{2}{7}}{\frac{49}{35}-\frac{25}{35}}$$

Since \frac{49}{35} and \frac{25}{35} have the same denominator, subtract them by subtracting their numerators.

$$0+\frac{\frac{2}{7}}{\frac{49-25}{35}}$$

Subtract 25 from 49 to get 24.

$$0+\frac{\frac{2}{7}}{\frac{24}{35}}$$

Divide \frac{2}{7} by \frac{24}{35} by multiplying \frac{2}{7} by the reciprocal of \frac{24}{35}.

$$0+\frac{2}{7}\times \frac{35}{24}$$

Multiply \frac{2}{7} times \frac{35}{24} by multiplying numerator times numerator and denominator times denominator.

$$0+\frac{2\times 35}{7\times 24}$$

Do the multiplications in the fraction \frac{2\times 35}{7\times 24}.

$$0+\frac{70}{168}$$

Reduce the fraction \frac{70}{168} to lowest terms by extracting and canceling out 14.

$$0+\frac{5}{12}$$

Add 0 and \frac{5}{12} to get \frac{5}{12}.

$$\frac{5}{12}$$

Factor

$$\frac{5}{3 \cdot 2 ^ {2}} = 0.4166666666666667$$