Solve 21/12-41/6+1

$$2 \frac{ 1 }{ 12 } -4 \frac{ 1 }{ 6 } +1$$

Evaluate

$$-\frac{13}{12}\approx -1.083333333$$

Solution Steps

Multiply 2 and 12 to get 24.

$$\frac{24+1}{12}-\frac{4\times 6+1}{6}+1$$

Add 24 and 1 to get 25.

$$\frac{25}{12}-\frac{4\times 6+1}{6}+1$$

Multiply 4 and 6 to get 24.

$$\frac{25}{12}-\frac{24+1}{6}+1$$

Add 24 and 1 to get 25.

$$\frac{25}{12}-\frac{25}{6}+1$$

Least common multiple of 12 and 6 is 12. Convert \frac{25}{12} and \frac{25}{6} to fractions with denominator 12.

$$\frac{25}{12}-\frac{50}{12}+1$$

Since \frac{25}{12} and \frac{50}{12} have the same denominator, subtract them by subtracting their numerators.

$$\frac{25-50}{12}+1$$

Subtract 50 from 25 to get -25.

$$-\frac{25}{12}+1$$

Convert 1 to fraction \frac{12}{12}.

$$-\frac{25}{12}+\frac{12}{12}$$

Since -\frac{25}{12} and \frac{12}{12} have the same denominator, add them by adding their numerators.

$$\frac{-25+12}{12}$$

Add -25 and 12 to get -13.

$$-\frac{13}{12}$$

Factor

$$-\frac{13}{12} = -1\frac{1}{12} = -1.0833333333333333$$