Solve 28/16+3/16*22/16=

$$2 \frac { 8 } { 16 } + \frac { 3 } { 16 } \cdot 2 \frac { 2 } { 16 } =$$

Evaluate

$$\frac{371}{128}=2.8984375$$

Solution Steps

Multiply 2 and 16 to get 32.

$$\frac{32+8}{16}+\frac{3}{16}\times \frac{2\times 16+2}{16}$$

Add 32 and 8 to get 40.

$$\frac{40}{16}+\frac{3}{16}\times \frac{2\times 16+2}{16}$$

Reduce the fraction \frac{40}{16} to lowest terms by extracting and canceling out 8.

$$\frac{5}{2}+\frac{3}{16}\times \frac{2\times 16+2}{16}$$

Multiply 2 and 16 to get 32.

$$\frac{5}{2}+\frac{3}{16}\times \frac{32+2}{16}$$

Add 32 and 2 to get 34.

$$\frac{5}{2}+\frac{3}{16}\times \frac{34}{16}$$

Reduce the fraction \frac{34}{16} to lowest terms by extracting and canceling out 2.

$$\frac{5}{2}+\frac{3}{16}\times \frac{17}{8}$$

Multiply \frac{3}{16} times \frac{17}{8} by multiplying numerator times numerator and denominator times denominator.

$$\frac{5}{2}+\frac{3\times 17}{16\times 8}$$

Do the multiplications in the fraction \frac{3\times 17}{16\times 8}.

$$\frac{5}{2}+\frac{51}{128}$$

Least common multiple of 2 and 128 is 128. Convert \frac{5}{2} and \frac{51}{128} to fractions with denominator 128.

$$\frac{320}{128}+\frac{51}{128}$$

Since \frac{320}{128} and \frac{51}{128} have the same denominator, add them by adding their numerators.

$$\frac{320+51}{128}$$

Add 320 and 51 to get 371.

$$\frac{371}{128}$$

Factor

$$\frac{7 \cdot 53}{2 ^ {7}} = 2\frac{115}{128} = 2.8984375$$