Solve 27/9+42/3-15/6

$$2 \frac { 7 } { 9 } + 4 \frac { 2 } { 3 } - 1 \frac { 5 } { 6 }$$

Evaluate

$$\frac{101}{18}\approx 5.611111111$$

Solution Steps

Multiply 2 and 9 to get 18.

$$\frac{18+7}{9}+\frac{4\times 3+2}{3}-\frac{1\times 6+5}{6}$$

Add 18 and 7 to get 25.

$$\frac{25}{9}+\frac{4\times 3+2}{3}-\frac{1\times 6+5}{6}$$

Multiply 4 and 3 to get 12.

$$\frac{25}{9}+\frac{12+2}{3}-\frac{1\times 6+5}{6}$$

Add 12 and 2 to get 14.

$$\frac{25}{9}+\frac{14}{3}-\frac{1\times 6+5}{6}$$

Least common multiple of 9 and 3 is 9. Convert \frac{25}{9} and \frac{14}{3} to fractions with denominator 9.

$$\frac{25}{9}+\frac{42}{9}-\frac{1\times 6+5}{6}$$

Since \frac{25}{9} and \frac{42}{9} have the same denominator, add them by adding their numerators.

$$\frac{25+42}{9}-\frac{1\times 6+5}{6}$$

Add 25 and 42 to get 67.

$$\frac{67}{9}-\frac{1\times 6+5}{6}$$

Multiply 1 and 6 to get 6.

$$\frac{67}{9}-\frac{6+5}{6}$$

Add 6 and 5 to get 11.

$$\frac{67}{9}-\frac{11}{6}$$

Least common multiple of 9 and 6 is 18. Convert \frac{67}{9} and \frac{11}{6} to fractions with denominator 18.

$$\frac{134}{18}-\frac{33}{18}$$

Since \frac{134}{18} and \frac{33}{18} have the same denominator, subtract them by subtracting their numerators.

$$\frac{134-33}{18}$$

Subtract 33 from 134 to get 101.

$$\frac{101}{18}$$

Factor

$$\frac{101}{2 \cdot 3 ^ {2}} = 5\frac{11}{18} = 5.611111111111111$$