Solve 26/8+43/10=

$$2 \frac { 6 } { 8 } + 4 \frac { 3 } { 10 } =$$

Evaluate

$$\frac{141}{20}=7.05$$

Solution Steps

Multiply 2 and 8 to get 16.

$$\frac{16+6}{8}+\frac{4\times 10+3}{10}$$

Add 16 and 6 to get 22.

$$\frac{22}{8}+\frac{4\times 10+3}{10}$$

Reduce the fraction \frac{22}{8} to lowest terms by extracting and canceling out 2.

$$\frac{11}{4}+\frac{4\times 10+3}{10}$$

Multiply 4 and 10 to get 40.

$$\frac{11}{4}+\frac{40+3}{10}$$

Add 40 and 3 to get 43.

$$\frac{11}{4}+\frac{43}{10}$$

Least common multiple of 4 and 10 is 20. Convert \frac{11}{4} and \frac{43}{10} to fractions with denominator 20.

$$\frac{55}{20}+\frac{86}{20}$$

Since \frac{55}{20} and \frac{86}{20} have the same denominator, add them by adding their numerators.

$$\frac{55+86}{20}$$

Add 55 and 86 to get 141.

$$\frac{141}{20}$$

Factor

$$\frac{3 \cdot 47}{2 ^ {2} \cdot 5} = 7\frac{1}{20} = 7.05$$