Solve 25/6-41/3=

$$2 \frac { 5 } { 6 } - 4 \frac { 1 } { 3 } =$$

Evaluate

$$-\frac{3}{2}=-1.5$$

Solution Steps

Multiply 2 and 6 to get 12.

$$\frac{12+5}{6}-\frac{4\times 3+1}{3}$$

Add 12 and 5 to get 17.

$$\frac{17}{6}-\frac{4\times 3+1}{3}$$

Multiply 4 and 3 to get 12.

$$\frac{17}{6}-\frac{12+1}{3}$$

Add 12 and 1 to get 13.

$$\frac{17}{6}-\frac{13}{3}$$

Least common multiple of 6 and 3 is 6. Convert \frac{17}{6} and \frac{13}{3} to fractions with denominator 6.

$$\frac{17}{6}-\frac{26}{6}$$

Since \frac{17}{6} and \frac{26}{6} have the same denominator, subtract them by subtracting their numerators.

$$\frac{17-26}{6}$$

Subtract 26 from 17 to get -9.

$$\frac{-9}{6}$$

Reduce the fraction \frac{-9}{6} to lowest terms by extracting and canceling out 3.

$$-\frac{3}{2}$$

Factor

$$-\frac{3}{2} = -1\frac{1}{2} = -1.5$$