Solve 25/5-x^2/-x=

$$2 \frac { 5 } { 5 } - \frac { x ^ { 2 } } { - x } =$$

Evaluate

$$x+3$$

Short Solution Steps

Multiply 2 and 5 to get 10.

$$\frac{10+5}{5}-\frac{x^{2}}{-x}$$

Add 10 and 5 to get 15.

$$\frac{15}{5}-\frac{x^{2}}{-x}$$

Divide 15 by 5 to get 3.

$$3-\frac{x^{2}}{-x}$$

To add or subtract expressions, expand them to make their denominators the same. Multiply 3 times \frac{-x}{-x}.

$$\frac{3\left(-1\right)x}{-x}-\frac{x^{2}}{-x}$$

Since \frac{3\left(-1\right)x}{-x} and \frac{x^{2}}{-x} have the same denominator, subtract them by subtracting their numerators.

$$\frac{3\left(-1\right)x-x^{2}}{-x}$$

Do the multiplications in 3\left(-1\right)x-x^{2}.

$$\frac{-3x-x^{2}}{-x}$$

Factor the expressions that are not already factored in \frac{-3x-x^{2}}{-x}.

$$\frac{x\left(-x-3\right)}{-x}$$

Cancel out x in both numerator and denominator.

$$\frac{-x-3}{-1}$$

Anything divided by -1 gives its opposite. To find the opposite of -x-3, find the opposite of each term.

$$x+3$$

Expand

$$x+3$$

Short Solution Steps

Multiply 2 and 5 to get 10.

$$\frac{10+5}{5}-\frac{x^{2}}{-x}$$

Add 10 and 5 to get 15.

$$\frac{15}{5}-\frac{x^{2}}{-x}$$

Divide 15 by 5 to get 3.

$$3-\frac{x^{2}}{-x}$$

To add or subtract expressions, expand them to make their denominators the same. Multiply 3 times \frac{-x}{-x}.

$$\frac{3\left(-1\right)x}{-x}-\frac{x^{2}}{-x}$$

Since \frac{3\left(-1\right)x}{-x} and \frac{x^{2}}{-x} have the same denominator, subtract them by subtracting their numerators.

$$\frac{3\left(-1\right)x-x^{2}}{-x}$$

Do the multiplications in 3\left(-1\right)x-x^{2}.

$$\frac{-3x-x^{2}}{-x}$$

Factor the expressions that are not already factored in \frac{-3x-x^{2}}{-x}.

$$\frac{x\left(-x-3\right)}{-x}$$

Cancel out x in both numerator and denominator.

$$\frac{-x-3}{-1}$$

Anything divided by -1 gives its opposite. To find the opposite of -x-3, find the opposite of each term.

$$x+3$$