Solve 25/14+3^2/21-63/10

$$2 \frac { 5 } { 14 } + 3 ^ { 2 } / 21 - 6 \frac { 3 } { 10 }$$

Evaluate

$$-\frac{123}{35}\approx -3.514285714$$

Solution Steps

Multiply 2 and 14 to get 28.

$$\frac{28+5}{14}+\frac{3^{2}}{21}-\frac{6\times 10+3}{10}$$

Add 28 and 5 to get 33.

$$\frac{33}{14}+\frac{3^{2}}{21}-\frac{6\times 10+3}{10}$$

Calculate 3 to the power of 2 and get 9.

$$\frac{33}{14}+\frac{9}{21}-\frac{6\times 10+3}{10}$$

Reduce the fraction \frac{9}{21} to lowest terms by extracting and canceling out 3.

$$\frac{33}{14}+\frac{3}{7}-\frac{6\times 10+3}{10}$$

Least common multiple of 14 and 7 is 14. Convert \frac{33}{14} and \frac{3}{7} to fractions with denominator 14.

$$\frac{33}{14}+\frac{6}{14}-\frac{6\times 10+3}{10}$$

Since \frac{33}{14} and \frac{6}{14} have the same denominator, add them by adding their numerators.

$$\frac{33+6}{14}-\frac{6\times 10+3}{10}$$

Add 33 and 6 to get 39.

$$\frac{39}{14}-\frac{6\times 10+3}{10}$$

Multiply 6 and 10 to get 60.

$$\frac{39}{14}-\frac{60+3}{10}$$

Add 60 and 3 to get 63.

$$\frac{39}{14}-\frac{63}{10}$$

Least common multiple of 14 and 10 is 70. Convert \frac{39}{14} and \frac{63}{10} to fractions with denominator 70.

$$\frac{195}{70}-\frac{441}{70}$$

Since \frac{195}{70} and \frac{441}{70} have the same denominator, subtract them by subtracting their numerators.

$$\frac{195-441}{70}$$

Subtract 441 from 195 to get -246.

$$\frac{-246}{70}$$

Reduce the fraction \frac{-246}{70} to lowest terms by extracting and canceling out 2.

$$-\frac{123}{35}$$

Factor

$$-\frac{123}{35} = -3\frac{18}{35} = -3.5142857142857142$$