Solve 23/9+64/5*83/41div6+21

$$2 \frac { 3 } { 9 } + 6 \frac { 4 } { 5 } \times \frac { 83 } { 41 } \div 6 + 21$$

Evaluate

$$\frac{15761}{615}\approx 25.627642276$$

Solution Steps

Multiply 2 and 9 to get 18.

$$\frac{18+3}{9}+\frac{\frac{6\times 5+4}{5}\times \frac{83}{41}}{6}+21$$

Add 18 and 3 to get 21.

$$\frac{21}{9}+\frac{\frac{6\times 5+4}{5}\times \frac{83}{41}}{6}+21$$

Reduce the fraction \frac{21}{9} to lowest terms by extracting and canceling out 3.

$$\frac{7}{3}+\frac{\frac{6\times 5+4}{5}\times \frac{83}{41}}{6}+21$$

Multiply 6 and 5 to get 30.

$$\frac{7}{3}+\frac{\frac{30+4}{5}\times \frac{83}{41}}{6}+21$$

Add 30 and 4 to get 34.

$$\frac{7}{3}+\frac{\frac{34}{5}\times \frac{83}{41}}{6}+21$$

Multiply \frac{34}{5} times \frac{83}{41} by multiplying numerator times numerator and denominator times denominator.

$$\frac{7}{3}+\frac{\frac{34\times 83}{5\times 41}}{6}+21$$

Do the multiplications in the fraction \frac{34\times 83}{5\times 41}.

$$\frac{7}{3}+\frac{\frac{2822}{205}}{6}+21$$

Express \frac{\frac{2822}{205}}{6} as a single fraction.

$$\frac{7}{3}+\frac{2822}{205\times 6}+21$$

Multiply 205 and 6 to get 1230.

$$\frac{7}{3}+\frac{2822}{1230}+21$$

Reduce the fraction \frac{2822}{1230} to lowest terms by extracting and canceling out 2.

$$\frac{7}{3}+\frac{1411}{615}+21$$

Least common multiple of 3 and 615 is 615. Convert \frac{7}{3} and \frac{1411}{615} to fractions with denominator 615.

$$\frac{1435}{615}+\frac{1411}{615}+21$$

Since \frac{1435}{615} and \frac{1411}{615} have the same denominator, add them by adding their numerators.

$$\frac{1435+1411}{615}+21$$

Add 1435 and 1411 to get 2846.

$$\frac{2846}{615}+21$$

Convert 21 to fraction \frac{12915}{615}.

$$\frac{2846}{615}+\frac{12915}{615}$$

Since \frac{2846}{615} and \frac{12915}{615} have the same denominator, add them by adding their numerators.

$$\frac{2846+12915}{615}$$

Add 2846 and 12915 to get 15761.

$$\frac{15761}{615}$$

Factor

$$\frac{15761}{3 \cdot 5 \cdot 41} = 25\frac{386}{615} = 25.627642276422765$$