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\left(2\times 5+3\right)x+40=10-5x
Multiply both sides of the equation by 5.
\left(10+3\right)x+40=10-5x
Multiply 2 and 5 to get 10.
13x+40=10-5x
Add 10 and 3 to get 13.
13x+40+5x=10
Add 5x to both sides.
18x+40=10
Combine 13x and 5x to get 18x.
18x=10-40
Subtract 40 from both sides.
18x=-30
Subtract 40 from 10 to get -30.
x=\frac{-30}{18}
Divide both sides by 18.
x=-\frac{5}{3}
Reduce the fraction \frac{-30}{18} to lowest terms by extracting and canceling out 6.