Solve for b
b>\frac{47}{15}
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3\left(2\times 5+3\right)<15b-8
Multiply both sides of the equation by 15, the least common multiple of 5,15. Since 15 is positive, the inequality direction remains the same.
3\left(10+3\right)<15b-8
Multiply 2 and 5 to get 10.
3\times 13<15b-8
Add 10 and 3 to get 13.
39<15b-8
Multiply 3 and 13 to get 39.
15b-8>39
Swap sides so that all variable terms are on the left hand side. This changes the sign direction.
15b>39+8
Add 8 to both sides.
15b>47
Add 39 and 8 to get 47.
b>\frac{47}{15}
Divide both sides by 15. Since 15 is positive, the inequality direction remains the same.
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