Solve 23/4*(2*2/5*2-7/10)

$$2 \frac { 3 } { 4 } \times ( \frac { 2 \times 2 } { 5 \times 2 } - \frac { 7 } { 10 } )$$

Evaluate

$$-\frac{33}{40}=-0.825$$

Solution Steps

Multiply 2 and 4 to get 8.

$$\frac{8+3}{4}\left(\frac{2\times 2}{5\times 2}-\frac{7}{10}\right)$$

Add 8 and 3 to get 11.

$$\frac{11}{4}\left(\frac{2\times 2}{5\times 2}-\frac{7}{10}\right)$$

Cancel out 2 in both numerator and denominator.

$$\frac{11}{4}\left(\frac{2}{5}-\frac{7}{10}\right)$$

Least common multiple of 5 and 10 is 10. Convert \frac{2}{5} and \frac{7}{10} to fractions with denominator 10.

$$\frac{11}{4}\left(\frac{4}{10}-\frac{7}{10}\right)$$

Since \frac{4}{10} and \frac{7}{10} have the same denominator, subtract them by subtracting their numerators.

$$\frac{11}{4}\times \frac{4-7}{10}$$

Subtract 7 from 4 to get -3.

$$\frac{11}{4}\left(-\frac{3}{10}\right)$$

Multiply \frac{11}{4} times -\frac{3}{10} by multiplying numerator times numerator and denominator times denominator.

$$\frac{11\left(-3\right)}{4\times 10}$$

Do the multiplications in the fraction \frac{11\left(-3\right)}{4\times 10}.

$$\frac{-33}{40}$$

Fraction \frac{-33}{40} can be rewritten as -\frac{33}{40} by extracting the negative sign.

$$-\frac{33}{40}$$

Factor

$$-\frac{33}{40} = -0.825$$