Solve 22/7div31/5

$$2 \frac { 2 } { 7 } \div 3 \frac { 1 } { 5 }$$

Evaluate

$$\frac{5}{7}\approx 0.714285714$$

Solution Steps

Divide \frac{2\times 7+2}{7} by \frac{3\times 5+1}{5} by multiplying \frac{2\times 7+2}{7} by the reciprocal of \frac{3\times 5+1}{5}.

$$\frac{\left(2\times 7+2\right)\times 5}{7\left(3\times 5+1\right)}$$

Multiply 2 and 7 to get 14.

$$\frac{\left(14+2\right)\times 5}{7\left(3\times 5+1\right)}$$

Add 14 and 2 to get 16.

$$\frac{16\times 5}{7\left(3\times 5+1\right)}$$

Multiply 16 and 5 to get 80.

$$\frac{80}{7\left(3\times 5+1\right)}$$

Multiply 3 and 5 to get 15.

$$\frac{80}{7\left(15+1\right)}$$

Add 15 and 1 to get 16.

$$\frac{80}{7\times 16}$$

Multiply 7 and 16 to get 112.

$$\frac{80}{112}$$

Reduce the fraction \frac{80}{112} to lowest terms by extracting and canceling out 16.

$$\frac{5}{7}$$

Factor

$$\frac{5}{7} = 0.7142857142857143$$