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\frac{\left(2\times 5+2\right)\times 15}{5\times 7}
Divide \frac{2\times 5+2}{5} by \frac{7}{15} by multiplying \frac{2\times 5+2}{5} by the reciprocal of \frac{7}{15}.
\frac{3\left(2+2\times 5\right)}{7}
Cancel out 5 in both numerator and denominator.
\frac{3\left(2+10\right)}{7}
Multiply 2 and 5 to get 10.
\frac{3\times 12}{7}
Add 2 and 10 to get 12.
\frac{36}{7}
Multiply 3 and 12 to get 36.