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\frac{\left(2\times 5+2\right)\times 10}{5\times 3}-\frac{2}{10}
Divide \frac{2\times 5+2}{5} by \frac{3}{10} by multiplying \frac{2\times 5+2}{5} by the reciprocal of \frac{3}{10}.
\frac{2\left(2+2\times 5\right)}{3}-\frac{2}{10}
Cancel out 5 in both numerator and denominator.
\frac{2\left(2+10\right)}{3}-\frac{2}{10}
Multiply 2 and 5 to get 10.
\frac{2\times 12}{3}-\frac{2}{10}
Add 2 and 10 to get 12.
\frac{24}{3}-\frac{2}{10}
Multiply 2 and 12 to get 24.
8-\frac{2}{10}
Divide 24 by 3 to get 8.
8-\frac{1}{5}
Reduce the fraction \frac{2}{10} to lowest terms by extracting and canceling out 2.
\frac{40}{5}-\frac{1}{5}
Convert 8 to fraction \frac{40}{5}.
\frac{40-1}{5}
Since \frac{40}{5} and \frac{1}{5} have the same denominator, subtract them by subtracting their numerators.
\frac{39}{5}
Subtract 1 from 40 to get 39.