Solve 22/41*32/3

$$2 \frac { 2 } { 41 } \times 3 \frac { 2 } { 3 }$$

Evaluate

$$\frac{308}{41}\approx 7.512195122$$

Solution Steps

Multiply 2 and 41 to get 82.

$$\frac{82+2}{41}\times \frac{3\times 3+2}{3}$$

Add 82 and 2 to get 84.

$$\frac{84}{41}\times \frac{3\times 3+2}{3}$$

Multiply 3 and 3 to get 9.

$$\frac{84}{41}\times \frac{9+2}{3}$$

Add 9 and 2 to get 11.

$$\frac{84}{41}\times \frac{11}{3}$$

Multiply \frac{84}{41} times \frac{11}{3} by multiplying numerator times numerator and denominator times denominator.

$$\frac{84\times 11}{41\times 3}$$

Do the multiplications in the fraction \frac{84\times 11}{41\times 3}.

$$\frac{924}{123}$$

Reduce the fraction \frac{924}{123} to lowest terms by extracting and canceling out 3.

$$\frac{308}{41}$$

Factor

$$\frac{2 ^ {2} \cdot 7 \cdot 11}{41} = 7\frac{21}{41} = 7.512195121951219$$