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\frac{\left(2\times 3+2\right)\times 8}{3}
Divide \frac{2\times 3+2}{3} by \frac{1}{8} by multiplying \frac{2\times 3+2}{3} by the reciprocal of \frac{1}{8}.
\frac{\left(6+2\right)\times 8}{3}
Multiply 2 and 3 to get 6.
\frac{8\times 8}{3}
Add 6 and 2 to get 8.
\frac{64}{3}
Multiply 8 and 8 to get 64.