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\frac{\left(2\times 3+2\right)\times 3}{3}
Divide \frac{2\times 3+2}{3} by \frac{1}{3} by multiplying \frac{2\times 3+2}{3} by the reciprocal of \frac{1}{3}.
2\times 3+2
Cancel out 3 and 3.
6+2
Multiply 2 and 3 to get 6.
8
Add 6 and 2 to get 8.