Solve 22/3+(-8/9)*(-13/5)=

$$2 \frac { 2 } { 3 } + ( - \frac { 8 } { 9 } ) \times ( - 1 \frac { 3 } { 5 } ) =$$

Evaluate

$$\frac{184}{45}\approx 4.088888889$$

Solution Steps

Multiply 2 and 3 to get 6.

$$\frac{6+2}{3}-\frac{8}{9}\left(-\frac{5+3}{5}\right)$$

Add 6 and 2 to get 8.

$$\frac{8}{3}-\frac{8}{9}\left(-\frac{5+3}{5}\right)$$

Add 5 and 3 to get 8.

$$\frac{8}{3}-\frac{8}{9}\left(-\frac{8}{5}\right)$$

Multiply -\frac{8}{9} times -\frac{8}{5} by multiplying numerator times numerator and denominator times denominator.

$$\frac{8}{3}+\frac{-8\left(-8\right)}{9\times 5}$$

Do the multiplications in the fraction \frac{-8\left(-8\right)}{9\times 5}.

$$\frac{8}{3}+\frac{64}{45}$$

Least common multiple of 3 and 45 is 45. Convert \frac{8}{3} and \frac{64}{45} to fractions with denominator 45.

$$\frac{120}{45}+\frac{64}{45}$$

Since \frac{120}{45} and \frac{64}{45} have the same denominator, add them by adding their numerators.

$$\frac{120+64}{45}$$

Add 120 and 64 to get 184.

$$\frac{184}{45}$$

Factor

$$\frac{2 ^ {3} \cdot 23}{3 ^ {2} \cdot 5} = 4\frac{4}{45} = 4.088888888888889$$