Solve 21/80+6(2^2+3^2)-44^2

$$2 \frac { 1 } { 80 } + 6 ( 2 ^ { 2 } + 3 ^ { 2 } ) - 44 ^ { 2 }$$

Evaluate

$$-\frac{148479}{80}=-1855.9875$$

Solution Steps

Multiply 2 and 80 to get 160.

$$\frac{160+1}{80}+6\left(2^{2}+3^{2}\right)-44^{2}$$

Add 160 and 1 to get 161.

$$\frac{161}{80}+6\left(2^{2}+3^{2}\right)-44^{2}$$

Calculate 2 to the power of 2 and get 4.

$$\frac{161}{80}+6\left(4+3^{2}\right)-44^{2}$$

Calculate 3 to the power of 2 and get 9.

$$\frac{161}{80}+6\left(4+9\right)-44^{2}$$

Add 4 and 9 to get 13.

$$\frac{161}{80}+6\times 13-44^{2}$$

Multiply 6 and 13 to get 78.

$$\frac{161}{80}+78-44^{2}$$

Convert 78 to fraction \frac{6240}{80}.

$$\frac{161}{80}+\frac{6240}{80}-44^{2}$$

Since \frac{161}{80} and \frac{6240}{80} have the same denominator, add them by adding their numerators.

$$\frac{161+6240}{80}-44^{2}$$

Add 161 and 6240 to get 6401.

$$\frac{6401}{80}-44^{2}$$

Calculate 44 to the power of 2 and get 1936.

$$\frac{6401}{80}-1936$$

Convert 1936 to fraction \frac{154880}{80}.

$$\frac{6401}{80}-\frac{154880}{80}$$

Since \frac{6401}{80} and \frac{154880}{80} have the same denominator, subtract them by subtracting their numerators.

$$\frac{6401-154880}{80}$$

Subtract 154880 from 6401 to get -148479.

$$-\frac{148479}{80}$$

Factor

$$-\frac{148479}{80} = -1855\frac{79}{80} = -1855.9875$$