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\frac{\left(2\times 7+1\right)\times 14}{7\left(3\times 14+3\right)}-\frac{1\times 3+1}{3}\left(-\frac{1\times 2+1}{2}\right)^{3}
Divide \frac{2\times 7+1}{7} by \frac{3\times 14+3}{14} by multiplying \frac{2\times 7+1}{7} by the reciprocal of \frac{3\times 14+3}{14}.
\frac{2\left(1+2\times 7\right)}{3+3\times 14}-\frac{1\times 3+1}{3}\left(-\frac{1\times 2+1}{2}\right)^{3}
Cancel out 7 in both numerator and denominator.
\frac{2\left(1+14\right)}{3+3\times 14}-\frac{1\times 3+1}{3}\left(-\frac{1\times 2+1}{2}\right)^{3}
Multiply 2 and 7 to get 14.
\frac{2\times 15}{3+3\times 14}-\frac{1\times 3+1}{3}\left(-\frac{1\times 2+1}{2}\right)^{3}
Add 1 and 14 to get 15.
\frac{30}{3+3\times 14}-\frac{1\times 3+1}{3}\left(-\frac{1\times 2+1}{2}\right)^{3}
Multiply 2 and 15 to get 30.
\frac{30}{3+42}-\frac{1\times 3+1}{3}\left(-\frac{1\times 2+1}{2}\right)^{3}
Multiply 3 and 14 to get 42.
\frac{30}{45}-\frac{1\times 3+1}{3}\left(-\frac{1\times 2+1}{2}\right)^{3}
Add 3 and 42 to get 45.
\frac{2}{3}-\frac{1\times 3+1}{3}\left(-\frac{1\times 2+1}{2}\right)^{3}
Reduce the fraction \frac{30}{45} to lowest terms by extracting and canceling out 15.
\frac{2}{3}-\frac{3+1}{3}\left(-\frac{1\times 2+1}{2}\right)^{3}
Multiply 1 and 3 to get 3.
\frac{2}{3}-\frac{4}{3}\left(-\frac{1\times 2+1}{2}\right)^{3}
Add 3 and 1 to get 4.
\frac{2}{3}-\frac{4}{3}\left(-\frac{2+1}{2}\right)^{3}
Multiply 1 and 2 to get 2.
\frac{2}{3}-\frac{4}{3}\left(-\frac{3}{2}\right)^{3}
Add 2 and 1 to get 3.
\frac{2}{3}-\frac{4}{3}\left(-\frac{27}{8}\right)
Calculate -\frac{3}{2} to the power of 3 and get -\frac{27}{8}.
\frac{2}{3}-\left(-\frac{9}{2}\right)
Multiply \frac{4}{3} and -\frac{27}{8} to get -\frac{9}{2}.
\frac{2}{3}+\frac{9}{2}
The opposite of -\frac{9}{2} is \frac{9}{2}.
\frac{31}{6}
Add \frac{2}{3} and \frac{9}{2} to get \frac{31}{6}.