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\frac{\left(2\times 7+1\right)\times 4}{7\times 3}
Divide \frac{2\times 7+1}{7} by \frac{3}{4} by multiplying \frac{2\times 7+1}{7} by the reciprocal of \frac{3}{4}.
\frac{\left(14+1\right)\times 4}{7\times 3}
Multiply 2 and 7 to get 14.
\frac{15\times 4}{7\times 3}
Add 14 and 1 to get 15.
\frac{60}{7\times 3}
Multiply 15 and 4 to get 60.
\frac{60}{21}
Multiply 7 and 3 to get 21.
\frac{20}{7}
Reduce the fraction \frac{60}{21} to lowest terms by extracting and canceling out 3.