Solve 21/6+11/3+12/6=

$$2 \frac { 1 } { 6 } + 1 \frac { 1 } { 3 } + 1 \frac { 2 } { 6 } =$$

Evaluate

$$\frac{29}{6}\approx 4.833333333$$

Solution Steps

Multiply 2 and 6 to get 12.

$$\frac{12+1}{6}+\frac{1\times 3+1}{3}+\frac{1\times 6+2}{6}$$

Add 12 and 1 to get 13.

$$\frac{13}{6}+\frac{1\times 3+1}{3}+\frac{1\times 6+2}{6}$$

Multiply 1 and 3 to get 3.

$$\frac{13}{6}+\frac{3+1}{3}+\frac{1\times 6+2}{6}$$

Add 3 and 1 to get 4.

$$\frac{13}{6}+\frac{4}{3}+\frac{1\times 6+2}{6}$$

Least common multiple of 6 and 3 is 6. Convert \frac{13}{6} and \frac{4}{3} to fractions with denominator 6.

$$\frac{13}{6}+\frac{8}{6}+\frac{1\times 6+2}{6}$$

Since \frac{13}{6} and \frac{8}{6} have the same denominator, add them by adding their numerators.

$$\frac{13+8}{6}+\frac{1\times 6+2}{6}$$

Add 13 and 8 to get 21.

$$\frac{21}{6}+\frac{1\times 6+2}{6}$$

Reduce the fraction \frac{21}{6} to lowest terms by extracting and canceling out 3.

$$\frac{7}{2}+\frac{1\times 6+2}{6}$$

Multiply 1 and 6 to get 6.

$$\frac{7}{2}+\frac{6+2}{6}$$

Add 6 and 2 to get 8.

$$\frac{7}{2}+\frac{8}{6}$$

Reduce the fraction \frac{8}{6} to lowest terms by extracting and canceling out 2.

$$\frac{7}{2}+\frac{4}{3}$$

Least common multiple of 2 and 3 is 6. Convert \frac{7}{2} and \frac{4}{3} to fractions with denominator 6.

$$\frac{21}{6}+\frac{8}{6}$$

Since \frac{21}{6} and \frac{8}{6} have the same denominator, add them by adding their numerators.

$$\frac{21+8}{6}$$

Add 21 and 8 to get 29.

$$\frac{29}{6}$$

Factor

$$\frac{29}{2 \cdot 3} = 4\frac{5}{6} = 4.833333333333333$$