Solve 21/4-(21/6+1/3)

$$2 \frac { 1 } { 4 } - ( 2 \frac { 1 } { 6 } + \frac { 1 } { 3 } )$$

Evaluate

$$-\frac{1}{4}=-0.25$$

Solution Steps

Multiply 2 and 4 to get 8.

$$\frac{8+1}{4}-\left(\frac{2\times 6+1}{6}+\frac{1}{3}\right)$$

Add 8 and 1 to get 9.

$$\frac{9}{4}-\left(\frac{2\times 6+1}{6}+\frac{1}{3}\right)$$

Multiply 2 and 6 to get 12.

$$\frac{9}{4}-\left(\frac{12+1}{6}+\frac{1}{3}\right)$$

Add 12 and 1 to get 13.

$$\frac{9}{4}-\left(\frac{13}{6}+\frac{1}{3}\right)$$

Least common multiple of 6 and 3 is 6. Convert \frac{13}{6} and \frac{1}{3} to fractions with denominator 6.

$$\frac{9}{4}-\left(\frac{13}{6}+\frac{2}{6}\right)$$

Since \frac{13}{6} and \frac{2}{6} have the same denominator, add them by adding their numerators.

$$\frac{9}{4}-\frac{13+2}{6}$$

Add 13 and 2 to get 15.

$$\frac{9}{4}-\frac{15}{6}$$

Reduce the fraction \frac{15}{6} to lowest terms by extracting and canceling out 3.

$$\frac{9}{4}-\frac{5}{2}$$

Least common multiple of 4 and 2 is 4. Convert \frac{9}{4} and \frac{5}{2} to fractions with denominator 4.

$$\frac{9}{4}-\frac{10}{4}$$

Since \frac{9}{4} and \frac{10}{4} have the same denominator, subtract them by subtracting their numerators.

$$\frac{9-10}{4}$$

Subtract 10 from 9 to get -1.

$$-\frac{1}{4}$$

Factor

$$-\frac{1}{4} = -0.25$$