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\frac{\left(2\times 4+1\right)\times 8}{4\left(1\times 8+3\right)}
Divide \frac{2\times 4+1}{4} by \frac{1\times 8+3}{8} by multiplying \frac{2\times 4+1}{4} by the reciprocal of \frac{1\times 8+3}{8}.
\frac{2\left(1+2\times 4\right)}{3+8}
Cancel out 4 in both numerator and denominator.
\frac{2\left(1+8\right)}{3+8}
Multiply 2 and 4 to get 8.
\frac{2\times 9}{3+8}
Add 1 and 8 to get 9.
\frac{18}{3+8}
Multiply 2 and 9 to get 18.
\frac{18}{11}
Add 3 and 8 to get 11.