Solve 21/3-31/2+41/4=

$$2 \frac { 1 } { 3 } - 3 \frac { 1 } { 2 } + 4 \frac { 1 } { 4 } =$$

Evaluate

$$\frac{37}{12}\approx 3.083333333$$

Solution Steps

Multiply 2 and 3 to get 6.

$$\frac{6+1}{3}-\frac{3\times 2+1}{2}+\frac{4\times 4+1}{4}$$

Add 6 and 1 to get 7.

$$\frac{7}{3}-\frac{3\times 2+1}{2}+\frac{4\times 4+1}{4}$$

Multiply 3 and 2 to get 6.

$$\frac{7}{3}-\frac{6+1}{2}+\frac{4\times 4+1}{4}$$

Add 6 and 1 to get 7.

$$\frac{7}{3}-\frac{7}{2}+\frac{4\times 4+1}{4}$$

Least common multiple of 3 and 2 is 6. Convert \frac{7}{3} and \frac{7}{2} to fractions with denominator 6.

$$\frac{14}{6}-\frac{21}{6}+\frac{4\times 4+1}{4}$$

Since \frac{14}{6} and \frac{21}{6} have the same denominator, subtract them by subtracting their numerators.

$$\frac{14-21}{6}+\frac{4\times 4+1}{4}$$

Subtract 21 from 14 to get -7.

$$-\frac{7}{6}+\frac{4\times 4+1}{4}$$

Multiply 4 and 4 to get 16.

$$-\frac{7}{6}+\frac{16+1}{4}$$

Add 16 and 1 to get 17.

$$-\frac{7}{6}+\frac{17}{4}$$

Least common multiple of 6 and 4 is 12. Convert -\frac{7}{6} and \frac{17}{4} to fractions with denominator 12.

$$-\frac{14}{12}+\frac{51}{12}$$

Since -\frac{14}{12} and \frac{51}{12} have the same denominator, add them by adding their numerators.

$$\frac{-14+51}{12}$$

Add -14 and 51 to get 37.

$$\frac{37}{12}$$

Factor

$$\frac{37}{2 ^ {2} \cdot 3} = 3\frac{1}{12} = 3.0833333333333335$$