Solve 21/3-19/12

$$2 \frac { 1 } { 3 } - 1 \frac { 9 } { 12 }$$

Evaluate

$$\frac{7}{12}\approx 0.583333333$$

Solution Steps

Multiply 2 and 3 to get 6.

$$\frac{6+1}{3}-\frac{1\times 12+9}{12}$$

Add 6 and 1 to get 7.

$$\frac{7}{3}-\frac{1\times 12+9}{12}$$

Multiply 1 and 12 to get 12.

$$\frac{7}{3}-\frac{12+9}{12}$$

Add 12 and 9 to get 21.

$$\frac{7}{3}-\frac{21}{12}$$

Reduce the fraction \frac{21}{12} to lowest terms by extracting and canceling out 3.

$$\frac{7}{3}-\frac{7}{4}$$

Least common multiple of 3 and 4 is 12. Convert \frac{7}{3} and \frac{7}{4} to fractions with denominator 12.

$$\frac{28}{12}-\frac{21}{12}$$

Since \frac{28}{12} and \frac{21}{12} have the same denominator, subtract them by subtracting their numerators.

$$\frac{28-21}{12}$$

Subtract 21 from 28 to get 7.

$$\frac{7}{12}$$

Factor

$$\frac{7}{2 ^ {2} \cdot 3} = 0.5833333333333334$$