Solve 21/3-7/12=

$$2 \frac { 1 } { 3 } - \frac { 7 } { 12 } =$$

Evaluate

$$\frac{7}{4}=1.75$$

Solution Steps

Multiply 2 and 3 to get 6.

$$\frac{6+1}{3}-\frac{7}{12}$$

Add 6 and 1 to get 7.

$$\frac{7}{3}-\frac{7}{12}$$

Least common multiple of 3 and 12 is 12. Convert \frac{7}{3} and \frac{7}{12} to fractions with denominator 12.

$$\frac{28}{12}-\frac{7}{12}$$

Since \frac{28}{12} and \frac{7}{12} have the same denominator, subtract them by subtracting their numerators.

$$\frac{28-7}{12}$$

Subtract 7 from 28 to get 21.

$$\frac{21}{12}$$

Reduce the fraction \frac{21}{12} to lowest terms by extracting and canceling out 3.

$$\frac{7}{4}$$

Factor

$$\frac{7}{2 ^ {2}} = 1\frac{3}{4} = 1.75$$