Solve 21/3*21/7-12/3:5/9

$$2 \frac { 1 } { 3 } \times 2 \frac { 1 } { 7 } - 1 \frac { 2 } { 3 } : \frac { 5 } { 9 }$$

Evaluate

$$2$$

Solution Steps

Multiply 2 and 3 to get 6.

$$\frac{6+1}{3}\times \frac{2\times 7+1}{7}-\frac{\frac{1\times 3+2}{3}}{\frac{5}{9}}$$

Add 6 and 1 to get 7.

$$\frac{7}{3}\times \frac{2\times 7+1}{7}-\frac{\frac{1\times 3+2}{3}}{\frac{5}{9}}$$

Multiply 2 and 7 to get 14.

$$\frac{7}{3}\times \frac{14+1}{7}-\frac{\frac{1\times 3+2}{3}}{\frac{5}{9}}$$

Add 14 and 1 to get 15.

$$\frac{7}{3}\times \frac{15}{7}-\frac{\frac{1\times 3+2}{3}}{\frac{5}{9}}$$

Multiply \frac{7}{3} times \frac{15}{7} by multiplying numerator times numerator and denominator times denominator.

$$\frac{7\times 15}{3\times 7}-\frac{\frac{1\times 3+2}{3}}{\frac{5}{9}}$$

Cancel out 7 in both numerator and denominator.

$$\frac{15}{3}-\frac{\frac{1\times 3+2}{3}}{\frac{5}{9}}$$

Divide 15 by 3 to get 5.

$$5-\frac{\frac{1\times 3+2}{3}}{\frac{5}{9}}$$

Divide \frac{1\times 3+2}{3} by \frac{5}{9} by multiplying \frac{1\times 3+2}{3} by the reciprocal of \frac{5}{9}.

$$5-\frac{\left(1\times 3+2\right)\times 9}{3\times 5}$$

Cancel out 3 in both numerator and denominator.

$$5-\frac{3\left(2+3\right)}{5}$$

Add 2 and 3 to get 5.

$$5-\frac{3\times 5}{5}$$

Multiply 3 and 5 to get 15.

$$5-\frac{15}{5}$$

Divide 15 by 5 to get 3.

$$5-3$$

Subtract 3 from 5 to get 2.

$$2$$

Factor

$$2$$