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\frac{\left(2\times 3+1\right)\times 5}{3\left(2\times 5+4\right)}
Divide \frac{2\times 3+1}{3} by \frac{2\times 5+4}{5} by multiplying \frac{2\times 3+1}{3} by the reciprocal of \frac{2\times 5+4}{5}.
\frac{\left(6+1\right)\times 5}{3\left(2\times 5+4\right)}
Multiply 2 and 3 to get 6.
\frac{7\times 5}{3\left(2\times 5+4\right)}
Add 6 and 1 to get 7.
\frac{35}{3\left(2\times 5+4\right)}
Multiply 7 and 5 to get 35.
\frac{35}{3\left(10+4\right)}
Multiply 2 and 5 to get 10.
\frac{35}{3\times 14}
Add 10 and 4 to get 14.
\frac{35}{42}
Multiply 3 and 14 to get 42.
\frac{5}{6}
Reduce the fraction \frac{35}{42} to lowest terms by extracting and canceling out 7.