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\frac{\left(2\times 3+1\right)\times 7}{3\times 5}
Divide \frac{2\times 3+1}{3} by \frac{5}{7} by multiplying \frac{2\times 3+1}{3} by the reciprocal of \frac{5}{7}.
\frac{\left(6+1\right)\times 7}{3\times 5}
Multiply 2 and 3 to get 6.
\frac{7\times 7}{3\times 5}
Add 6 and 1 to get 7.
\frac{49}{3\times 5}
Multiply 7 and 7 to get 49.
\frac{49}{15}
Multiply 3 and 5 to get 15.