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\frac{\left(2\times 3+1\right)\times 3}{3\left(6\times 3+2\right)}
Divide \frac{2\times 3+1}{3} by \frac{6\times 3+2}{3} by multiplying \frac{2\times 3+1}{3} by the reciprocal of \frac{6\times 3+2}{3}.
\frac{1+2\times 3}{2+3\times 6}
Cancel out 3 in both numerator and denominator.
\frac{1+6}{2+3\times 6}
Multiply 2 and 3 to get 6.
\frac{7}{2+3\times 6}
Add 1 and 6 to get 7.
\frac{7}{2+18}
Multiply 3 and 6 to get 18.
\frac{7}{20}
Add 2 and 18 to get 20.