Solve 21/3:(11/6-7)*1/4

$$2 \frac { 1 } { 3 } : ( 1 \frac { 1 } { 6 } - 7 ) \cdot \frac { 1 } { 4 }$$

Evaluate

$$-\frac{1}{10}=-0.1$$

Solution Steps

Multiply 2 and 3 to get 6.

$$\frac{\frac{6+1}{3}}{\frac{1\times 6+1}{6}-7}\times \frac{1}{4}$$

Add 6 and 1 to get 7.

$$\frac{\frac{7}{3}}{\frac{1\times 6+1}{6}-7}\times \frac{1}{4}$$

Multiply 1 and 6 to get 6.

$$\frac{\frac{7}{3}}{\frac{6+1}{6}-7}\times \frac{1}{4}$$

Add 6 and 1 to get 7.

$$\frac{\frac{7}{3}}{\frac{7}{6}-7}\times \frac{1}{4}$$

Convert 7 to fraction \frac{42}{6}.

$$\frac{\frac{7}{3}}{\frac{7}{6}-\frac{42}{6}}\times \frac{1}{4}$$

Since \frac{7}{6} and \frac{42}{6} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\frac{7}{3}}{\frac{7-42}{6}}\times \frac{1}{4}$$

Subtract 42 from 7 to get -35.

$$\frac{\frac{7}{3}}{-\frac{35}{6}}\times \frac{1}{4}$$

Divide \frac{7}{3} by -\frac{35}{6} by multiplying \frac{7}{3} by the reciprocal of -\frac{35}{6}.

$$\frac{7}{3}\left(-\frac{6}{35}\right)\times \frac{1}{4}$$

Multiply \frac{7}{3} times -\frac{6}{35} by multiplying numerator times numerator and denominator times denominator.

$$\frac{7\left(-6\right)}{3\times 35}\times \frac{1}{4}$$

Do the multiplications in the fraction \frac{7\left(-6\right)}{3\times 35}.

$$\frac{-42}{105}\times \frac{1}{4}$$

Reduce the fraction \frac{-42}{105} to lowest terms by extracting and canceling out 21.

$$-\frac{2}{5}\times \frac{1}{4}$$

Multiply -\frac{2}{5} times \frac{1}{4} by multiplying numerator times numerator and denominator times denominator.

$$\frac{-2}{5\times 4}$$

Do the multiplications in the fraction \frac{-2}{5\times 4}.

$$\frac{-2}{20}$$

Reduce the fraction \frac{-2}{20} to lowest terms by extracting and canceling out 2.

$$-\frac{1}{10}$$

Factor

$$-\frac{1}{10} = -0.1$$