Solve 21/3+45/9-11/6=

$$2 \frac { 1 } { 3 } + 4 \frac { 5 } { 9 } - 1 \frac { 1 } { 6 } =$$

Evaluate

$$\frac{103}{18}\approx 5.722222222$$

Solution Steps

Multiply 2 and 3 to get 6.

$$\frac{6+1}{3}+\frac{4\times 9+5}{9}-\frac{1\times 6+1}{6}$$

Add 6 and 1 to get 7.

$$\frac{7}{3}+\frac{4\times 9+5}{9}-\frac{1\times 6+1}{6}$$

Multiply 4 and 9 to get 36.

$$\frac{7}{3}+\frac{36+5}{9}-\frac{1\times 6+1}{6}$$

Add 36 and 5 to get 41.

$$\frac{7}{3}+\frac{41}{9}-\frac{1\times 6+1}{6}$$

Least common multiple of 3 and 9 is 9. Convert \frac{7}{3} and \frac{41}{9} to fractions with denominator 9.

$$\frac{21}{9}+\frac{41}{9}-\frac{1\times 6+1}{6}$$

Since \frac{21}{9} and \frac{41}{9} have the same denominator, add them by adding their numerators.

$$\frac{21+41}{9}-\frac{1\times 6+1}{6}$$

Add 21 and 41 to get 62.

$$\frac{62}{9}-\frac{1\times 6+1}{6}$$

Multiply 1 and 6 to get 6.

$$\frac{62}{9}-\frac{6+1}{6}$$

Add 6 and 1 to get 7.

$$\frac{62}{9}-\frac{7}{6}$$

Least common multiple of 9 and 6 is 18. Convert \frac{62}{9} and \frac{7}{6} to fractions with denominator 18.

$$\frac{124}{18}-\frac{21}{18}$$

Since \frac{124}{18} and \frac{21}{18} have the same denominator, subtract them by subtracting their numerators.

$$\frac{124-21}{18}$$

Subtract 21 from 124 to get 103.

$$\frac{103}{18}$$

Factor

$$\frac{103}{2 \cdot 3 ^ {2}} = 5\frac{13}{18} = 5.722222222222222$$