Solve 21/3+44/7=

$$2 \frac { 1 } { 3 } + 4 \frac { 4 } { 7 } =$$

Evaluate

$$\frac{145}{21}\approx 6.904761905$$

Solution Steps

Multiply 2 and 3 to get 6.

$$\frac{6+1}{3}+\frac{4\times 7+4}{7}$$

Add 6 and 1 to get 7.

$$\frac{7}{3}+\frac{4\times 7+4}{7}$$

Multiply 4 and 7 to get 28.

$$\frac{7}{3}+\frac{28+4}{7}$$

Add 28 and 4 to get 32.

$$\frac{7}{3}+\frac{32}{7}$$

Least common multiple of 3 and 7 is 21. Convert \frac{7}{3} and \frac{32}{7} to fractions with denominator 21.

$$\frac{49}{21}+\frac{96}{21}$$

Since \frac{49}{21} and \frac{96}{21} have the same denominator, add them by adding their numerators.

$$\frac{49+96}{21}$$

Add 49 and 96 to get 145.

$$\frac{145}{21}$$

Factor

$$\frac{5 \cdot 29}{3 \cdot 7} = 6\frac{19}{21} = 6.904761904761905$$